What's keeping the crane from overturning? The RIGHTING MOMENT.

Think of it as the turning force on one side of a big see-saw- the load and the boom being

on the other side.

The
Righting Moment has 2 parts here. The moment of the crane body and the moment of the

counter weight-ct.wt.

First the crane body- it weighs 30# and
the CG is 1.6ft from the pivot

M = F x D

M = 30# x
1.6ft

M = 48ft#

,

Now for the ctwt. The 4 bricks weigh 20# and are 42" (3.5ft) from the pivot.

So M = F x D

M = 20#
x 3.5 ft = 70 ft#

TOTAL MOMENT 48 + 70 = 118ft#

That's a lot more than the 59.39ft# of OTM.

The
ratio of RM/OTM = 1.96 In the crane industry a ratio of 1.5 is the minimum,

so
with a ratio of almost 2, the crane will be stable with a ctwt. of 20#.

Now
let's say we have to land (or place) the load farther away-right now

3.46ft
is the farthest reach we have, so let's lengthen the boom by adding the jib.

First
we release the catch that holds the jib to the underside of the boom,

and
the jib swings down.

Then we lower the boom a bit and the jib rolls forward

We've removed the 4 load lines and replaced them with a single line that
goes from

the load windlass, over the single sheave mounted on the small
mast, and then down

to the tip of the jib. Now we can raise the jib.

Next we'll bolt it on to the boom and secure it with lines running from
the tip of the jib,

over the small mast, to an anchor point
in the middle of the boom.

Now we've got a boom that's 6.5 ft long, but will that change the Moment?

The force is the same -the 10# bucket, but the distance has increased.

cos 30 = Dist load /6.5ft

cos 30 = .866

.866 = D load/ 6.5ft

D load = 5.63ft

M = F x D

M = 10# x 5.63 ft

M = 56.3 ft#

What about the boom? It still
weighs 11#, but the CG, now that the jib has been extended, is 3.5ft

cos 30 = D boom / 3.5ft

cos 30 = .866

.866 = D boom/ 3.5ft

D boom = 3.03
ft

M = F x D

M
= 11# x 3.03ft

M = 33.33ft#

TOTAL
MOMENT 33.33 + 56.3 = 89.6ft#. That's a lot more than the 60ft# we had before.

The RM is still 118ft#, so our new ratio of RM/OTM is 1.37.

That's fine for a static situation- if the load is just hanging.

But if the load is moving up or down, or if the crane is slewing (swiveling) or if the wind

catches the load and makes it swing or ?????.

Then
we've got a DYNAMIC load, and the 118ft# of RM might not be enough.

So
we'll add 2 more bricks to make the ctwt. 30#

The moment of the crane body hasn't changed-it's still 48ft#, but the

moment of the ctwt. is now

M = F x D

M = 30# x 3.5ft

M = 105Ft#

TOTAL MOMENT = 48ft# + 105ft# = 153 ft#

and
the ratio of RM/OTM 153/86 = 1.77 well above the minimum 1.5

Did you notice that the center of mass pointer in the photo was at 26".

That wasn't right. I'll have a new page "how to find the CG"
soon.