This wood beam is 22" long and weighs 4 pounds (4#), and

the steel block (3" wide) weighs 7.375#

We attach slings with the hook centered over the middle of

the
beam and lift----oops!!!

We have to find the combined Center of Gravity--- CG.

First the wood
beam-If we assume the density of the beam

is uniform throughout its length, then the CG will
be in

the geometric center

You knew that already, just like the CG of a 12" ruler is

centered at 6"

Same with the steel block. It's 3" wide so the CG is 1 1/2"
in

from the edge.

But
when we put the 2 together, everything changes and we'd better

know where
the combined CG is or our load will tip and could injure someone.

Here's
how- let's assume the beam and the block are balanced on a pivot point

at 1 end and would therefore try to rotate- like a see-saw-- only with just 1 side.

Remember
forces that cause rotation can be computed using the basic formula for Moment-

M
= Force x Distance

For the pivot point we'll use one end of the wood beam-the
end opposite the steel block.

To compute the Moment of the beam
M = F x D

The force is the weight (4#) and the distance is measured from
the line of force to the pivot

(at a right angle). The line of force (gravity
remember) goes through the geometric

center of the beam- so the Dist is
11"

M = F x D

M = 4# x
11"

M = 44inch pounds-44"#

Now the steel block- wt = 7.375#.and the distance from the pivot is 20 1/2"

M = F x D

M = 7.375# x 20.5"=151.18"#

Here's the formula to find the combined CG

MOMENTbeam + MOMENT block divided by combined weight of

beam and block.

44"# + 151.18"# divided by 7.375# + 4# =

195.18"# /11.3745# =

17.1"

So now we place the hook directly above the CG (17.1" from pivot) and lift.